Electrical Eng. · Question Bank

Faults

40 questions · page 1 of 2. Answer in your head first, then check the solution.

#1
In symmetrical components, what is the vector sum of \(1 + a + a^2\)?
A1
B0
C-1
DInfinity
#2📜 EE Board October 1998
If the load of a wye-connected transformer are:
\(I_a = 10\text{ cis }(-30^\circ)\)
\(I_b = 12\text{ cis }215^\circ\)
\(I_c = 15\text{ cis }82^\circ\)
What is the phase b positive sequence component?
A\(13.4\text{ cis }(-32.2^\circ)\)
B\(10.2\text{ cis }240^\circ\)
C\(12.27\text{ cis }208.4^\circ\)
D\(12.27\text{ cis }(-31.6^\circ)\)
#3
Given three unbalanced three-phase voltages:
\(V_a = 150 + j0\text{ V}\)
\(V_b = -90 - j120\text{ V}\)
\(V_c = -120 + j90\text{ V}\)
Determine \(V_{a1}\).
A\(142.43 + j12.35\)
B\(135.32 - j21.34\)
C\(145.62 + j13.66\)
D\(140.23 - j9.32\)
#4📜 EE Board March 1998
The three-phase unbalanced currents are:
\(I_a = 10\text{ cis }(-30^\circ)\)
\(I_b = 0\)
\(I_c = 10\text{ cis }150^\circ\)
Find the negative sequence current of phase a.
A\(8.66\text{ cis }30^\circ\)
B\(5.77\text{ cis }(-60^\circ)\)
C-5.77
D5.77
#5📜 EE Board October 1984
Given the following currents:
\(I_a = 60 + j0\text{ A}\)
\(I_b = -36 - j48\text{ A}\)
\(I_c = -48 + j36\text{ A}\)
Solve for the negative sequence component of \(I_a\).
A\(8.641 - j1.543\)
B\(9.436 + j1.346\)
C\(9.751 - j1.464\)
D\(8.354 + j1.034\)
#6📜 EE Board October 1998
The three-phase unbalance currents are:
\(I_a = 10\text{ cis }(-30^\circ)\)
\(I_b = 0\)
\(I_c = 10\text{ cis }150^\circ\)
Find the zero sequence current.
A\(3.33\text{ cis }30^\circ\)
B0
C5.77
D3.33
#7📜 EE Board October 1984
Given the following currents:
\(I_a = 60 + j0\text{ A}\)
\(I_b = -36 - j48\text{ A}\)
\(I_c = -48 + j36\text{ A}\)
Solve for zero sequence component of \(I_a\).
A\(10 + j4\)
B\(8 - j6\)
C\(-8 - j4\)
D\(12 - j6\)
#8📜 EE Board October 1997
The sequence currents of phase a current are as follows:
Zero sequence current = \(14.13 \angle 17.34^\circ\)
Positive sequence current = \(2.98 \angle 10.06^\circ\)
Negative sequence current = \(708.26 \angle -31^\circ\)
Determine phase a current.
A\(720 \angle -30^\circ\)
B\(730 \angle -15.2^\circ\)
C\(710 \angle 88^\circ\)
D\(695 \angle 15.2^\circ\)
#9📜 EE Board October 1998
The sequence components of phase a current are:
Zero sequence component = \(0.47 + j1.49\)
Positive sequence component = \(18.4\text{ cis }(-31.6^\circ)\)
Negative sequence component = \(3.23\text{ cis }168.2^\circ\)
Determine the phase b current.
A\(18\text{ cis }215^\circ\)
B\(15\text{ cis }240^\circ\)
C\(19\text{ cis }220^\circ\)
D\(20\text{ cis }225^\circ\)
#10📜 EE Board March 1998
The sequence components of phase a current are:
Zero sequence = \(0.47 + j1.49\)
Positive sequence = \(18.4\text{ cis }(-31.6^\circ)\)
Negative sequence = \(3.23\text{ cis }168.2^\circ\)
Determine the phase c current.
A\(17.5\text{ cis }91^\circ\)
B\(18\text{ cis }215^\circ\)
C\(22.5\text{ cis }82^\circ\)
D\(15\text{ cis }100^\circ\)
#11📜 EE Board April 1992
Determine the symmetrical components of the line current in line 'a' if one of the in phase impedance of its delta-connected load connected across lines 'ca' is removed. The delta load with impedance of \(10 \angle 0^\circ\) ohms per phase is supplied from a 220 volts, 60 cycle, 3-phase. Assume a phase sequence of a-b-c.
A\(I_{a1} = 11\text{ A}, I_{a2} = 11\text{ A}, I_{a0} = 0\text{ A}\)
B\(I_{a1} = 7.33\text{ A}, I_{a2} = 7.33\text{ A}, I_{a0} = 7.33\text{ A}\)
C\(I_{a1} = 22\text{ A}, I_{a2} = 22\text{ A}, I_{a0} = 22\text{ A}\)
D\(I_{a1} = 25.4\text{ A}, I_{a2} = 12.7\text{ A}, I_{a0} = 0\text{ A}\)
#12📜 EE Board April 1991
A star-connected balanced load takes 75 A from a balanced 3-phase, 4-wire supply. If the two supply lines of the fuses are removed determine the symmetrical components of the line currents after the fuses are removed.
A\(I_1 = 25\text{ A}, I_2 = 25\text{ A}, I_0 = 25\text{ A}\)
B\(I_1 = 25\text{ A}, I_2 = 50\text{ A}, I_0 = 0\text{ A}\)
C\(I_1 = 75\text{ A}, I_2 = 75\text{ A}, I_0 = 75\text{ A}\)
D\(I_1 = 75\text{ A}, I_0 = 0\text{ A}\)
#13📜 EE Board March 1998
A 50 MVA, 33 kV/11 kV, three-phase, wye-delta connected transformer has a 3% impedance. What is the percent impedance at 100 MVA base and 34.5 kV base?
A1.639%
B5.49%
C5.74%
D6.56%
#14
At a certain location of an electrical system, the available short circuit MVA is 10 at 110 kV while its Thevenin's equivalent reactance is 0.05 pu. Determine the per unit reactance of this point using a base 20 MVA and 115 kV?
A0.08
B0.07
C0.06
D0.09
#15
A 13.8 kV/440 V, 50 kVA single-phase transformer has a leakage reactance of 300 ohms referred to the 13.8 kV side. Determine the per unit value of the leakage reactance for the voltage base.
A0.074
B0.082
C0.083
D0.079
#16📜 EE Board April 1980
A 5 kVA, 2400-120/240 volt distribution transformer when given a short circuit test had 94.2 volts applied with rated current flowing in the short-circuited wiring. What is the per unit impedance of the transformer?
A0.0392 ohms
B0.0386 ohms
C0.0415 ohms
D0.0435 ohms
#17
A 3-phase, 375 kVA, 480 V, 50 Hz, wye connected alternator has an equal positive and negative sequence reactance of 10%. Find the symmetrical fault current, if a 3-phase fault occurs at the alternator terminals.
A4510.5 A
B4620.3 A
C4255.2 A
D4778.1 A
#18📜 EE Board April 1992
A generator rated 600 kVA, 2400 V, 60 cycles, 3-phase, 6-poles and wye-connected has 10% synchronous reactance. If a three-phase fault occurs, what will be the short circuit current?
A1443 A
B1532 A
C1435 A
D1428 A
#19
A 20 MVA, 13.8 kV, 60 Hz, three-phase synchronous turbo alternator has a positive, negative and zero sequence reactances of 0.25, 0.35 and 0.15 respectively. If lines b and c are short-circuited, determine the subtransient fault current in line b. Assume the alternator is operating at no load and at rated voltage with the neutral of the alternator solidly grounded.
A2614 A
B2886 A
C2415 A
D2510 A
#20📜 EE Board March 1998
At a certain location in an electric system, the available fault MVA is 400 MVA. A 15 MVA, 34.5 kV/6.24 kV, 2.5% impedance, wye-wye grounded transformer is installed at that location. Determine the short circuit MVA at the secondary side of the transformer.
A195 MVA
B150 MVA
C90 MVA
D240 MVA

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