Sag and Tension Calculator with Ice and Wind Loading

Engineering Disclaimer: This content is for educational/informational purposes only. Always verify calculations and designs with a licensed engineer before applying them to actual construction or projects.
01

Sag and Tension Calculator

Choose a conductor from the list to fill in its properties, or type your own values. Set the initial (stringing) condition, then the final loading condition you want to check, and press Calculate.

Conductor

Initial conditions

The conditions when the conductor was first strung.

Final loading conditions

The conditions with wind, ice or maximum temperature.

Calculating…
Reminder: This calculator uses a linear elastic model for a level span. It does not include plastic elongation or creep, and it assumes the final modulus of elasticity stays constant. Always verify calculations and designs with a licensed engineer before applying them to actual construction or projects.
02

What to Enter and What You Get Back

The calculator compares two states of the same span: the day the conductor was strung, and the loading case you are checking.

Which conductors are in the list?

Six ACSR sizes (Sparrow, Quail, Penguin, Linnet, Dove, Condor) and one all-aluminum conductor (Arbutus, 795 kcmil). Selecting one fills in its coefficient of thermal expansion, final modulus of elasticity, area and diameter. The conductor weight and rated strength are taken from the same record. You can overwrite any of the four property fields if your supplier’s data sheet gives different values.

What goes into the initial and final conditions?

  • Span (m) — the level span between supports.
  • Initial tension (N) — the horizontal tension you string to, usually taken from your stringing chart at the erection temperature.
  • Initial temperature (°C) — the conductor temperature at stringing.
  • Final temperature (°C) — the case you are checking, such as maximum operating temperature for ground clearance.
  • Ice thickness (m) — radial ice on the conductor. Enter it in metres (12.7 mm = 0.0127 m). Set it to 0 for regions with no ice, including the Philippines.
  • Wind pressure (N/m²) — pressure on the projected area of the conductor (and ice, if any).
Watch the ice units. 0.05 m is 50 mm of radial ice, which is far heavier than most design codes require. On small conductors it drives the final tension past the breaking strength. The calculator warns you when the final tension goes above 100% of the conductor’s ultimate strength.

What do the results mean?

  • Wice, Wwind, Wresultant — the loads per metre of conductor. The resultant combines the vertical load (conductor plus ice) with the horizontal wind load.
  • Blowout angle — how far the conductor swings from vertical under wind. Use it for clearance to structures and between phases.
  • A and B — the coefficients of the change-of-state cubic that gives the final tension.
  • Final horizontal tension — the tension at the final condition, also shown as a percent of the conductor’s rated strength.
  • Initial sag and final sag — catenary sags at the two conditions. Final sag is measured along the plane of the resultant load.
  • Final vertical and horizontal sag — the final sag split into its vertical part (for ground clearance) and its sideways part (for swing clearance).
03

How the Calculator Works

There are three steps: work out the loads, solve the change-of-state equation for the final tension, then compute the sags with the catenary equation.

How are the ice and wind loads calculated?

Weight of radial ice per metre, with ice density taken as 915 kg/m³
\( W_{ice} = \rho_{ice}\, g\, \pi\, t\,(D + t) \)
Wind load per metre on the iced diameter
\( W_{wind} = p\,(D + 2t) \)
Resultant load and blowout angle
\( W = \sqrt{(w + W_{ice})^2 + W_{wind}^2} \qquad \theta = \tan^{-1}\!\left(\dfrac{W_{wind}}{w + W_{ice}}\right) \)

Variables

  • w — bare conductor weight, N/m (mass per metre × 9.81)
  • D — conductor diameter, m
  • t — radial ice thickness, m
  • p — wind pressure, N/m²

How is the final tension found?

The calculator uses the parabolic change-of-state equation. The conductor’s length change from temperature and from elastic stretch has to match the change in the geometric length of the curve. Rearranged, that gives a cubic in the final horizontal tension H₂.

Change-of-state equation in cubic form
\( H_2^3 + A\,H_2^2 – B = 0 \)
Coefficients of the cubic
\( A = \dfrac{w^2 S^2 EA}{24\,H_1^2} – H_1 + \alpha\, EA\,(t_2 – t_1) \qquad B = \dfrac{W^2 S^2 EA}{24} \)

Variables

  • H₁ — initial horizontal tension, N
  • S — span, m
  • E, A — final modulus of elasticity (N/m²) and cross-sectional area (m²)
  • α — coefficient of thermal expansion, 1/°C
  • t₁, t₂ — initial and final temperatures, °C
Because B is always positive, the cubic has exactly one positive root. That root is the final tension, so you never have to choose between solutions.

How are the sags calculated?

Catenary sag at midspan for a level span
\( D = \dfrac{H}{W}\left[\cosh\!\left(\dfrac{S\,W}{2H}\right) – 1\right] \)
Vertical and horizontal parts of the final sag
\( D_v = D_2 \cos\theta \qquad D_h = D_2 \sin\theta \)

The initial sag uses the bare weight w and H₁. The final sag uses the resultant load W and H₂. For why the catenary form is used here instead of wS²/8H, see the role of catenary equations in sag and tension.

04

Worked Example: Dove ACSR on a 300 m Span

These are the same numbers the calculator returns. Enter them yourself to compare.

Example inputs
ConductorDove, 556.5 kcmil 26/7 ACSR
w1.14238 kg/m × 9.81 = 11.2068 N/m
EA75.5 × 10⁹ N/m² × 0.0003279 m² = 24,756,450 N
α1.92 × 10⁻⁵ /°C
Span300 m
InitialH₁ = 10,000 N at 25 °C

How much does the sag grow at a higher conductor temperature?

Take a final temperature of 40 °C with no ice and no wind, so W = w.

Initial sag — H₁ = 10,000 N, w = 11.2068 N/m
D₁ = (10,000 / 11.2068)·[cosh(300 × 11.2068 / (2 × 10,000)) − 1]
= 12.637 m
Cubic coefficients — t₂ = 40 °C
A = 113,725.49    B = 1.16596 × 10¹³
H₂ = 9,718.65 N (9.7% of rated strength)
Final sag at 40 °C
D₂ = (9,718.65 / 11.2068)·[cosh(300 × 11.2068 / (2 × 9,718.65)) − 1]
= 13.005 m, about 0.37 m more than at stringing

What happens under a strong wind?

Keep the temperature at 25 °C and apply a wind pressure of 700 N/m². This is an illustration value, not a code requirement. Use the design wind pressure from your governing code.

Dove, 300 m, 25 °C, p = 700 N/m², no ice
ResultValue
Wwind16.4813 N/m
Wresultant19.9305 N/m
Blowout angle55.79°
Final horizontal tension17,255.50 N (17.3% of rated strength)
Final sag (along the resultant)13.027 m
Vertical sag7.325 m
Horizontal sag (swing)10.772 m
Wind barely changes the total sag here. It raises the tension and tilts the sag plane, so most of the sag turns into sideways swing. Check the 10.8 m horizontal sag against your phase spacing and structure clearances, not just the vertical sag against ground.
05

Limitations and When to Use EPE or SPE

This is a quick check, not a full stringing analysis.

What does this calculator leave out?

  • Plastic elongation and creep — ignored. Real conductors stretch permanently over time, which increases final sag.
  • Modulus — one final modulus of elasticity is used for the whole conductor. For ACSR, the aluminum and steel layers actually share load differently at high temperature.
  • Span geometry — level span only, with supports at the same height.
  • Change of state — solved with the parabolic approximation, while the sags use the full catenary. For normal sag-to-span ratios, the difference is small.
When creep or high-temperature operation matters, use the EPE sag and tension calculator or the linear and SPE calculator. They model plastic elongation and the stress-strain behavior of the conductor.
06

Summary of Equations

Loads
\( W_{ice} = \rho_{ice} g \pi t (D + t) \qquad W_{wind} = p (D + 2t) \qquad W = \sqrt{(w + W_{ice})^2 + W_{wind}^2} \)
Change of state
\( H_2^3 + A H_2^2 – B = 0, \quad A = \dfrac{w^2 S^2 EA}{24 H_1^2} – H_1 + \alpha EA (t_2 – t_1), \quad B = \dfrac{W^2 S^2 EA}{24} \)
Sag and blowout
\( D = \dfrac{H}{W}\left[\cosh\!\left(\dfrac{SW}{2H}\right) – 1\right], \quad \theta = \tan^{-1}\!\dfrac{W_{wind}}{w + W_{ice}}, \quad D_v = D_2\cos\theta, \quad D_h = D_2\sin\theta \)

For the full set of sag-tension formulas, including inclined spans and ruling span, see the sag and tension formulas cheat sheet.

Summary: This calculator takes a conductor from its stringing condition to a final temperature, ice and wind case. It works out the resultant load, solves the parabolic change-of-state cubic for the final horizontal tension, and gives the catenary sag split into vertical and horizontal parts. Use it for quick clearance and swing checks on level spans. Use the EPE or SPE calculators when plastic elongation, creep or high-temperature behavior matters.

References: CIGRE Technical Brochure 324, Sag-Tension Calculation Methods for Overhead Lines (2007). F. Kießling, P. Nefzger, J. F. Nolasco, U. Kaintzyk, Overhead Power Lines: Planning, Design, Construction (Springer, 2003).

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