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Faults

41 of 106 questions match · page 2 of 3. Answer in your head first, then check the solution.

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#21📜 EE Board October 1997📘 1001 RojasMedium
A 15 MVA, 34.5 kV/6.24 kV transformer is connected at an infinite bus. The percent impedance of the transformer is 2.5%. What is the current at the 34.5 kV side for a three phase short at the 6.24 kV side?
A55,500 A
B10,000 A
C5,000 A
D25,000 A
#22📜 EE Board April 1985📘 1001 RojasMedium
A three-phase, 3-wire generator is rated 325 kVA, 480 volts, 60 Hz with a reactance of eight (8) percent. Solve for the fault current delivered by the generator during a 2-phase short circuit at the terminals.
A4232 A
B4462 A
C4012 A
D4156 A
#23📘 1001 RojasMedium
Determine the minimum rupturing capacity of the circuit breaker as shown, if a three-phase symmetrical fault occurs at point P.
A30 MVA
B20 MVA
C10 MVA
D15 MVA
#24📜 EE Pre-Board August 2012📘 PowerhouseMedium
The following are the symmetrical components of phase B current: Positive Sequence Component = \(10\ \text{cis}\ 45^\circ\), Negative Sequence Component = \(20\ \text{cis}\ (-30^\circ)\), Zero Sequence Component = 0.5 + j0.9. Determine the positive sequence component of Phase A.
A\(20\ \text{cis}\ (-195^\circ)\)
B\(10\ \text{cis}\ 195^\circ\)
C\(10\ \text{cis}\ (-195^\circ)\)
D\(10\ \text{cis}\ (-30^\circ)\)
#25📜 EE Pre-Board August 2012📘 PowerhouseMedium
A 13.8 kV distribution line has a Thevenin’s equivalent impedance of 2.63%. If a phase to phase fault occurs between phase B and C, determine the fault current at 10 MVA base.
A13,000 A
B7,950 A
C5,300 A
D15,900 A
#26📜 EE Pre-Board March 2013📘 PowerhouseMedium
A 15 MVA, 34.5 kV / 6.24 kV transformer is connected at an infinite bus. The percent impedance of the transformer is 2.5%. What is the current at the 34.5 kV side for a three-phase fault at the 6.24 kV side?
A25,000 A
B5,000 A
C55,500 A
D10,000 A
#27📜 EE Pre-Board March 2013📘 PowerhouseMedium
At a certain point of the system network the positive, negative and zero sequence impedances are 0.25 p.u., 0.25 p.u. and 0.3 p.u., respectively. The base MVA is 100. The voltage level at that point is 34.5 kV. Determine the zero sequence current for a one-line ground fault.
A8.132 A
B7,516 A
C6,275 A
D2,091 A
#28📜 EE Pre-Board August 2013📘 PowerhouseMedium
The per unit reactances of a synchronous generator are \(X_d = 1\), \(X_d' = 0.35\) and \(X_d'' = 0.25\). The generator supplies a 1.0 per unit load at 0.8 power factor lagging. Calculate the voltage behind the subtransient reactance.
A1.79 pu
B1.24 pu
C1.17 pu
D1.59 pu
#29📜 EE Pre-Board August 2013📘 PowerhouseMedium
Three unbalanced 3-phase currents are given as follows: \(I_a = 10\angle -30^\circ\) A, \(I_b = 0\) and \(I_c = 10\angle -150^\circ\) A. Find \(I_{c1}\).
A\(3.34\angle 150^\circ\) A
B\(3.34\angle -150^\circ\) A
C\(3.34\angle 210^\circ\) A
D\(3.34\angle -135^\circ\) A
#30📜 EE Pre-Board March 2014📘 PowerhouseMedium
The positive, negative and zero-sequence reactances of a 20 MVA, 13.2 kV synchronous generator are 0.3 pu, 0.2 pu and 0.1 pu, respectively. The generator is solidly grounded and is not loaded. A line to ground fault occurs on phase a. Neglecting all the resistances, determine the fault current.
A2,916 A
B4,374
C2,525
D5,050
#31📜 EE Pre-Board March 2014📘 PowerhouseMedium
In a short circuit analysis, the positive, negative, and zero sequence impedances are 0.20 pu, 0.20 pu, and 0.25 pu, respectively, using a base MVA of 50. Estimate the fault current on the faulted lines if a line to line fault at the 138 kV level occurs.
A1,204 A
B2,718 A
C1,569 A
D906 A
#32📜 EE Pre-Board August 2014📘 PowerhouseMedium
In a 13.8 kV, 10 MVA base three phase system, a phase to phase fault occurs. If the Thevenin’s equivalent impedance of the system is 2.63%, what is the magnitude of the fault current?
A13,800 A
B15,900 A
C27,600 A
D7,970 A
#33📜 EE Pre-Board August 2014📘 PowerhouseMedium
The three unbalanced currents are \(I_a = 10\ \text{cis}\ (-30^\circ)\), \(I_b = 0\) and \(I_c = 10\ \text{cis}\ 150^\circ\). Find the phase C positive sequence current.
A5.77 A
B\(5.77\ \text{cis}\ 120^\circ\)
C\(8.66\ \text{cis}\ 120^\circ\)
D\(5.77\ \text{cis}\ 240^\circ\)
#34📜 EE Pre-Board March 2015📘 PowerhouseMedium
At a certain point of the system network the positive, negative and zero sequence impedances are 0.25 pu, 0.25 pu, 0.3 pu, respectively. The base MVA is 100. The level at that point is 34.5 KV. Determine the zero sequence current for a one line to ground fault.
A6,275 A
B7,516 A
C8,132 A
D2,091A
#35📜 EE Pre-Board August 2015📘 PowerhouseMedium
Given three unbalanced line currents \(I_a = 0 + j12\) A, \(I_b = 5 - j10\) A and \(I_c = -10 - j5\) A. Find the negative sequence component of \(I_c\) in amperes.
A\(3.12\angle -14.3^\circ\)
B\(3.12\angle 14.3^\circ\)
C\(2.25\angle -14.3^\circ\)
D\(2.25\angle 14.3^\circ\)
#36📜 EE Pre-Board August 2015📘 PowerhouseMedium
A 5-MVA, 13.8 kV/480 V, 5% impedance transformer is tapped at a 13.8 kV line where the Thevenin’s equivalent impedance is 0.5 Ω. Determine the fault current at the primary for a three-phase fault at the secondary.
A10,500 A
B4,200 A
C6,050 A
D3,300 A
#37📜 EE Pre-Board March 2016📘 PowerhouseMedium
The positive, negative, and zero sequence reactances of a 20-MVA, 13.2 kV synchronous generator are 0.3 pu, 0.2 pu and 0.1 pu, respectively. The generator is solidly grounded and is not loaded. A line to ground fault occurs on phase a. Neglecting all the resistances, determine the positive sequence component of the fault current.
A4,374A
B1,458A
C2,525 A
D7,576A
#38📜 EE Pre-Board March 2017📘 PowerhouseMedium
In a 3-phase, 4-wire system the currents in the a, b, and c lines under an abnormal condition of loading are \(I_a = 100\angle 30^\circ\) A, \(I_b = 50\angle 300^\circ\) A and \(I_c = 30\angle 180^\circ\) A. Find the zero sequence current.
A\(18.3\angle 6.81^\circ\) A
B\(17.3\angle 3.15^\circ\) A
C\(6.71\angle 5.4^\circ\) A
D\(27.29\angle 4.69^\circ\) A
#39📜 EE Pre-Board August 2017📘 PowerhouseMedium
Given three unbalanced line currents \(I_a = 0 + j12\) A, \(I_b = 5 - j10\) A and \(I_c = -10 - j5\) A. Find the negative sequence component of \(I_c\) in amperes.
A\(2.25\angle 105.7^\circ\)
B\(2.25\angle -134.3^\circ\)
C\(2.25\angle -14.3^\circ\)
D\(3.12\angle -14.3^\circ\)
#40📜 EE Pre-Board March 2018📘 PowerhouseMedium
Three unbalanced 3-phase currents are given as follows: \(I_a = 10\angle -30^\circ\) A, \(I_b = 0\), \(I_c = 10\angle -150^\circ\) A. Find the positive sequence component of \(I_a\).
A\(3.34\angle 150^\circ\) A
B\(3.34\angle -150^\circ\) A
C\(3.34\angle 30^\circ\) A
D\(3.34\angle -30^\circ\) A

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